<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom" xmlns:content="http://purl.org/rss/1.0/modules/content/"><channel><title>VAE on Xu'Blog</title><link>https://xuquant.com/tags/vae/</link><description>Recent content in VAE on Xu'Blog</description><image><title>Xu'Blog</title><url>https://xuquant.com/og-default.png</url><link>https://xuquant.com/og-default.png</link></image><generator>Hugo -- 0.152.2</generator><language>zh</language><lastBuildDate>Mon, 25 May 2026 20:00:00 +0800</lastBuildDate><atom:link href="https://xuquant.com/tags/vae/index.xml" rel="self" type="application/rss+xml"/><item><title>熵与信息论：从 -log p 到深度学习</title><link>https://xuquant.com/posts/mathematics/probability/entropy-and-information/</link><pubDate>Mon, 25 May 2026 20:00:00 +0800</pubDate><guid>https://xuquant.com/posts/mathematics/probability/entropy-and-information/</guid><description>从公理化角度推出 -log p 的必然性，依次过熵、互信息、KL 散度、最大熵原理，再回到深度学习里反复出现的几种形态——交叉熵损失、ELBO、信息瓶颈、最大熵强化学习。</description></item><item><title>得分匹配、GAN 与生成模型的统一</title><link>https://xuquant.com/posts/mathematics/probability/score-matching-gan/</link><pubDate>Mon, 11 May 2026 09:00:00 +0800</pubDate><guid>https://xuquant.com/posts/mathematics/probability/score-matching-gan/</guid><description>从 Hyvarinen 得分匹配到去噪得分匹配，从 GAN 的对抗训练到得分函数，建立 VAE、GAN、扩散模型在分布匹配框架下的统一理解。</description></item><item><title>变分自编码器：从 ELBO 到重参数化</title><link>https://xuquant.com/posts/mathematics/probability/vae-elbo/</link><pubDate>Sat, 02 May 2026 09:00:00 +0800</pubDate><guid>https://xuquant.com/posts/mathematics/probability/vae-elbo/</guid><description>从生成模型的推断难题出发，推导 ELBO 的两种等价形式，解释重参数化技巧的必要性，分析 VAE 的信息瓶颈与后验坍塌问题。</description></item><item><title>扩散模型的变分基础：从 ELBO 到去噪</title><link>https://xuquant.com/posts/mathematics/diffusion/ddpm-variational/</link><pubDate>Sat, 18 Apr 2026 09:00:00 +0800</pubDate><guid>https://xuquant.com/posts/mathematics/diffusion/ddpm-variational/</guid><description>从 ELBO 推导 DDPM 的变分下界，解释三项分解的物理意义，证明预测噪声与预测数据的等价性，建立扩散训练的变分理解。</description></item></channel></rss>